(8y^2+2)-(4-2y^2)=

Solution for (8y^2+2)-(4-2y^2)= equation:

Simplifying
(8y2 + 2) + -1(4 + -2y2) = 0

Reorder the terms:
(2 + 8y2) + -1(4 + -2y2) = 0

Remove parenthesis around (2 + 8y2)
2 + 8y2 + -1(4 + -2y2) = 0
2 + 8y2 + (4 * -1 + -2y2 * -1) = 0
2 + 8y2 + (-4 + 2y2) = 0

Reorder the terms:
2 + -4 + 8y2 + 2y2 = 0

Combine like terms: 2 + -4 = -2
-2 + 8y2 + 2y2 = 0

Combine like terms: 8y2 + 2y2 = 10y2
-2 + 10y2 = 0

Solving
-2 + 10y2 = 0

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + 10y2 = 0 + 2

Combine like terms: -2 + 2 = 0
0 + 10y2 = 0 + 2
10y2 = 0 + 2

Combine like terms: 0 + 2 = 2
10y2 = 2

Divide each side by '10'.
y2 = 0.2

Simplifying
y2 = 0.2

Take the square root of each side:
y = {-0.447213596, 0.447213596}